What is expand 2(3e^{-2x}+4e^x) ?

The solution to expand 2(3e^{-2x}+4e^x) is 6e^{-2x}+8e^x

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expand 2(3e^{-2x}+4e^x)

expand

2 (3 e^{- 2 x} + 4 e^{x})

6 e^{- 2 x} + 8 e^{x}

Solution steps

2 (3 e^{- 2 x} + 4 e^{x})

Apply the distributive law:

a (b + c) = ab + a c

a = 2, b = 3 e^{- 2 x}, c = 4 e^{x}

= 2 \cdot 3 e^{- 2 x} + 2 \cdot 4 e^{x}

Simplify

2 \cdot 3 e^{- 2 x} + 2 \cdot 4 e^{x} : 6 e^{- 2 x} + 8 e^{x}

= 6 e^{- 2 x} + 8 e^{x}

(2 (a - m c + n e) + m r (e - l)) r (e - l)

ln (e - (e + 2) (e - 2))

\frac{40}{s ^{2} ( s ^{2} + 16 )}

2 (a - 2 x - 6, - 6 + 2 y) - (4 y + 2, - 5 x - 1)

\frac{x + 2}{( x - 2 ) ( 1 - x )}

What is expand 2(3e^{-2x}+4e^x) ?
The solution to expand 2(3e^{-2x}+4e^x) is 6e^{-2x}+8e^x