What is expand dy(y=5x^2-3x+2/x-1) ?

The solution to expand dy(y=5x^2-3x+2/x-1) is ydy=5x^2-3xdy+(2dy)/x-dy

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expand dy(y=5x^2-3x+2/x-1)

expand

d y (y = 5 x^{2} - 3 x + \frac{2}{x} - 1)

y d y = 5 x^{2} - 3 x d y + \frac{2 d y}{x} - d y

Solution steps

d y (y = 5 x^{2} - 3 x + \frac{2}{x} - 1)

= d y (5 = y x^{2} - 3 x + \frac{2}{x} - 1)

Distribute parentheses

d yy = 5 x^{2} + d y (- 3 x) + d y \frac{2}{x} + d y (- 1)

Apply minus-plus rules

+ (- a) = - a

y d y = 5 x^{2} - 3 x d y + \frac{2}{x} d y - 1 \cdot d y

Expand

5 x^{2} - 3 x d y + \frac{2}{x} d y - 1 \cdot d y : 5 x^{2} - 3 x d y + \frac{2 d y}{x} - d y

y d y = 5 x^{2} - 3 x d y + \frac{2 d y}{x} - d y

m u lt i pl y (5 x - 4 x)

(9 x^{2} - 5 x) e^{x}

(e^{5 x} + 4)^{2}

ln (1 + a (e^{x} - 1))

\frac{n ^{2} ( n - 1 ) ^{2}}{4}

What is expand dy(y=5x^2-3x+2/x-1) ?
The solution to expand dy(y=5x^2-3x+2/x-1) is ydy=5x^2-3xdy+(2dy)/x-dy