What is expand (2x+3)\circ (x^2-2x+4) ?

The solution to expand (2x+3)\circ (x^2-2x+4) is 2\circ x^3-\circ x^2+2\circ x+12\circ

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expand (2x+3)\circ (x^2-2x+4)

expand

(2 x + 3) \circ (x^{2} - 2 x + 4)

2 \circ x^{3} - \circ x^{2} + 2 \circ x + 12 \circ

Solution steps

(2 x + 3) \circ (x^{2} - 2 x + 4)

= \circ (2 x + 3) (x^{2} - 2 x + 4)

Expand

(2 x + 3) (x^{2} - 2 x + 4) : 2 x^{3} - x^{2} + 2 x + 12

= \circ (2 x^{3} - x^{2} + 2 x + 12)

Expand

\circ (2 x^{3} - x^{2} + 2 x + 12) : 2 \circ x^{3} - \circ x^{2} + 2 \circ x + 12 \circ

= 2 \circ x^{3} - \circ x^{2} + 2 \circ x + 12 \circ

\frac{( - x + 20 ) ( x - 10 )}{2}

\frac{3 t + 2}{t ( 1 + t ^{2} )}

\frac{10 ( 10 + 129 )}{29}

(4 - 5 x + 2 x^{2}) (1 + x, 1 - x, x^{2})

((5 x + 2) \cdot (x + 9)) \cdot x

What is expand (2x+3)\circ (x^2-2x+4) ?
The solution to expand (2x+3)\circ (x^2-2x+4) is 2\circ x^3-\circ x^2+2\circ x+12\circ