What is expand ((-3x-8)(x-1))/9 ?

The solution to expand ((-3x-8)(x-1))/9 is -(x^2)/3-(5x)/9+8/9

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expand ((-3x-8)(x-1))/9

expand

\frac{( - 3 x - 8 ) ( x - 1 )}{9}

- \frac{x ^{2}}{3} - \frac{5 x}{9} + \frac{8}{9}

Solution steps

\frac{( - 3 x - 8 ) ( x - 1 )}{9}

Expand

(- 3 x - 8) (x - 1) : - 3 x^{2} - 5 x + 8

= \frac{- 3 x ^{2} - 5 x + 8}{9}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- 3 x ^{2} - 5 x + 8}{9} = - \frac{3 x ^{2}}{9} - \frac{5 x}{9} + \frac{8}{9}

= - \frac{3 x ^{2}}{9} - \frac{5 x}{9} + \frac{8}{9}

Cancel

\frac{3 x ^{2}}{9} : \frac{x ^{2}}{3}

= - \frac{x ^{2}}{3} - \frac{5 x}{9} + \frac{8}{9}

\frac{( x ^{2} - 9 ) ( x - 2 )}{3 x + 6}

\frac{2 A - 3}{2 ( A - 1 )}

L im x \Rightarrow 3 (2 x - 3)

[(3 ab + 5 c d)^{2}] [(4 e f - 6 g h)^{2}]

\frac{x + 2}{x ^{2} ( x + 4 )}

What is expand ((-3x-8)(x-1))/9 ?
The solution to expand ((-3x-8)(x-1))/9 is -(x^2)/3-(5x)/9+8/9