What are the solutions to the equation 0=-3x^2+5x+9 ?

The solutions to the equation 0=-3x^2+5x+9 are x=-(-5+sqrt(133))/6 ,x=(5+sqrt(133))/6

Find the zeros of 0=-3x^2+5x+9

The zeros of 0=-3x^2+5x+9 are x=-(-5+sqrt(133))/6 ,x=(5+sqrt(133))/6

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0 = - 3 x^{2} + 5 x + 9

x = - \frac{- 5 + 133}{6}, x = \frac{5 + 133}{6}

Decimal Notation

x = - 1.08876 \dots, x = 2.75542 \dots

Solution steps

0 = - 3 x^{2} + 5 x + 9

Switch sides

- 3 x^{2} + 5 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 3 ) \cdot 9}{2 ( - 3 )}

5^{2} - 4 (- 3) \cdot 9 = 133

x_{1, 2} = \frac{- 5 \pm 133}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 5 + 133}{2 ( - 3 )}, x_{2} = \frac{- 5 - 133}{2 ( - 3 )}

x = \frac{- 5 + 133}{2 ( - 3 )} : - \frac{- 5 + 133}{6}

x = \frac{- 5 - 133}{2 ( - 3 )} : \frac{5 + 133}{6}

The solutions to the quadratic equation are:

x = - \frac{- 5 + 133}{6}, x = \frac{5 + 133}{6}

3 + \frac{1}{x} \leq 3

x^{2} - 4 x \geq 0

10 x^{2} + 15 x

12 x^{2} + 16 x < x^{4}

4 (2 n - 4) + 3 = 8 n - 19

What are the solutions to the equation 0=-3x^2+5x+9 ?
The solutions to the equation 0=-3x^2+5x+9 are x=-(-5+sqrt(133))/6 ,x=(5+sqrt(133))/6
Find the zeros of 0=-3x^2+5x+9
The zeros of 0=-3x^2+5x+9 are x=-(-5+sqrt(133))/6 ,x=(5+sqrt(133))/6