What is expand e^t(-e^{-t}t-e^{-t}+C) ?

The solution to expand e^t(-e^{-t}t-e^{-t}+C) is -t-1+Ce^t

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expand e^t(-e^{-t}t-e^{-t}+C)

expand

e^{t} (- e^{- t} t - e^{- t} + C)

- t - 1 + C e^{t}

Solution steps

e^{t} (- e^{- t} t - e^{- t} + C)

Distribute parentheses

= e^{t} (- e^{- t} t) + e^{t} (- e^{- t}) + e^{t} C

Apply minus-plus rules

+ (- a) = - a

= - e^{t} e^{- t} t - e^{t} e^{- t} + C e^{t}

Simplify

- e^{t} e^{- t} t - e^{t} e^{- t} + C e^{t} : - t - 1 + C e^{t}

= - t - 1 + C e^{t}

(4, - 10) y (7, r)

, (p + 3) (p - 2)

\frac{- x - 3}{h ^{2} ( x + h + 3 )}

4 p (t) (2 + \frac{4}{p ^{'} ( t )})

(- 3, - 8) (5, 6)^{'}

What is expand e^t(-e^{-t}t-e^{-t}+C) ?
The solution to expand e^t(-e^{-t}t-e^{-t}+C) is -t-1+Ce^t