What is expand 6(3x-1)e^{2x+1} ?

The solution to expand 6(3x-1)e^{2x+1} is 18e^{2x+1}x-6e^{2x+1}

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expand 6(3x-1)e^{2x+1}

expand

6 (3 x - 1) e^{2 x + 1}

18 e^{2 x + 1} x - 6 e^{2 x + 1}

Solution steps

6 (3 x - 1) e^{2 x + 1}

= 6 e^{2 x + 1} (3 x - 1)

Apply the distributive law:

a (b - c) = ab - a c

a = 6 e^{2 x + 1}, b = 3 x, c = 1

= 6 e^{2 x + 1} \cdot 3 x - 6 e^{2 x + 1} \cdot 1

= 6 \cdot 3 e^{2 x + 1} x - 6 \cdot 1 \cdot e^{2 x + 1}

Simplify

6 \cdot 3 e^{2 x + 1} x - 6 \cdot 1 \cdot e^{2 x + 1} : 18 e^{2 x + 1} x - 6 e^{2 x + 1}

= 18 e^{2 x + 1} x - 6 e^{2 x + 1}

b (2 a - b - 4 = 0)

e^{(t - 1) 2}

\frac{( 0.33 \cdot ( s + 2 ) )}{s}

(- 4 + i 9) \cdot (4 + i 9,)

\frac{18}{( t + 3 ) ^{2}}

What is expand 6(3x-1)e^{2x+1} ?
The solution to expand 6(3x-1)e^{2x+1} is 18e^{2x+1}x-6e^{2x+1}