What is expand ((x+1)^2)/((x-1)(x-3)) ?

The solution to expand ((x+1)^2)/((x-1)(x-3)) is (x^2+2x+1)/(x^2-4x+3)

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expand ((x+1)^2)/((x-1)(x-3))

expand

\frac{( x + 1 ) ^{2}}{( x - 1 ) ( x - 3 )}

\frac{x ^{2} + 2 x + 1}{x ^{2} - 4 x + 3}

Solution steps

\frac{( x + 1 ) ^{2}}{( x - 1 ) ( x - 3 )}

(x + 1)^{2} = x^{2} + 2 x + 1

= \frac{x ^{2} + 2 x + 1}{( x - 1 ) ( x - 3 )}

Expand

(x - 1) (x - 3) : x^{2} - 4 x + 3

= \frac{x ^{2} + 2 x + 1}{x ^{2} - 4 x + 3}

(2 x^{2} + 3 x - 3) e^{x}

\frac{40}{( z ^{2} + 16 ) z ^{2}}

\frac{1 - 3 x ^{2}}{( 1 - x ^{2} ) ^{2}}

\frac{2 ( 4 a + 4 )}{a + 9}

\frac{x ( x - 8 )}{2}

What is expand ((x+1)^2)/((x-1)(x-3)) ?
The solution to expand ((x+1)^2)/((x-1)(x-3)) is (x^2+2x+1)/(x^2-4x+3)