What is expand (2x-1)(e^xx-e^x+2) ?

The solution to expand (2x-1)(e^xx-e^x+2) is 2e^xx^2-3e^xx+4x+e^x-2

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expand (2x-1)(e^xx-e^x+2)

expand

(2 x - 1) (e^{x} x - e^{x} + 2)

2 e^{x} x^{2} - 3 e^{x} x + 4 x + e^{x} - 2

Solution steps

(2 x - 1) (e^{x} x - e^{x} + 2)

Distribute parentheses

= 2 x e^{x} x + 2 x (- e^{x}) + 2 x \cdot 2 + (- 1) e^{x} x + (- 1) (- e^{x}) + (- 1) \cdot 2

Apply minus-plus rules

+ (- a) = - a, (- a) (- b) = ab

= 2 e^{x} xx - 2 e^{x} x + 2 \cdot 2 x - 1 \cdot e^{x} x + 1 \cdot e^{x} - 1 \cdot 2

Simplify

2 e^{x} xx - 2 e^{x} x + 2 \cdot 2 x - 1 \cdot e^{x} x + 1 \cdot e^{x} - 1 \cdot 2 : 2 e^{x} x^{2} - 3 e^{x} x + 4 x + e^{x} - 2

= 2 e^{x} x^{2} - 3 e^{x} x + 4 x + e^{x} - 2

y (15 y + 31 = 61)

(e^{x} - e^{- x}) (e^{x} + 1)

(y + 6) (y + 6)^{'}

\frac{( x - 4 ) ^{2}}{( 2 - 5 x )}

\frac{d}{d t} ((x) (80 cos (x) + 20))

What is expand (2x-1)(e^xx-e^x+2) ?
The solution to expand (2x-1)(e^xx-e^x+2) is 2e^xx^2-3e^xx+4x+e^x-2