What is expand 3(2x-(3x+1)=x+1) ?

The solution to expand 3(2x-(3x+1)=x+1) is -3x-3=x+3

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expand 3(2x-(3x+1)=x+1)

expand

3 (2 x - (3 x + 1) = x + 1)

- 3 x - 3 = x + 3

Solution steps

3 (2 x - (3 x + 1) = x + 1)

= 3 (2 x - = x (3 x + 1) + 1)

Distribute parentheses

= 3 \cdot 2 x + 3 (- (3 x + 1) = x) + 3 \cdot 1

Apply minus-plus rules

+ (- a) = - a

3 \cdot 2 x - 3 (3 x + 1) = x + 3 \cdot 1

Simplify

3 \cdot 2 x - 3 (3 x + 1) = x + 3 \cdot 1 : - 3 x - 3 = x + 3

- 3 x - 3 = x + 3

(\frac{2 ( i - 1 )}{2})^{2}

\frac{π}{3} (25 - y^{2}) (y + 5)

\frac{4 x + 7}{( 6 x + 3 ) ( x - 6 )}

3 x - 3 \cdot \frac{3}{4}

- \frac{1 + x}{( 2 x + 1 ) ( x - 1 )}

What is expand 3(2x-(3x+1)=x+1) ?
The solution to expand 3(2x-(3x+1)=x+1) is -3x-3=x+3