What is expand (ln(n(n+1)))/(n+1) ?

The solution to expand (ln(n(n+1)))/(n+1) is (ln(n^2+n))/(n+1)

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expand (ln(n(n+1)))/(n+1)

expand

\frac{ln ( n ( n + 1 ) )}{n + 1}

\frac{ln ( n ^{2} + n )}{n + 1}

Solution steps

\frac{ln ( n ( n + 1 ) )}{n + 1}

Expand

n (n + 1) : n^{2} + n

= \frac{ln ( n ^{2} + n )}{n + 1}

x (x^{6} - 16 x^{4} = 0)

\frac{x + 2}{x ^{2} ( x + 1 )}

\frac{( 4 x + 8 )}{( ( x ^{2} - 1 ) ^{2} )}

(w (z) = 2, - 4 i) (z = 1 + i)

(5 + 3) 8 - 25

What is expand (ln(n(n+1)))/(n+1) ?
The solution to expand (ln(n(n+1)))/(n+1) is (ln(n^2+n))/(n+1)