What is the d/(dt)((x)(3x^3-30)) ?

The d/(dt)((x)(3x^3-30)) is 12t^3-30

What is the first d/(dt)((x)(3x^3-30)) ?

The first d/(dt)((x)(3x^3-30)) is 12t^3-30

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\frac{d}{d t} ((t) (3 t^{3} - 30))

12 t^{3} - 30

Solution steps

\frac{d}{d t} ((t) (3 t^{3} - 30))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = t, g = 3 t^{3} - 30

= \frac{d t}{d t} (3 t^{3} - 30) + \frac{d}{d t} (3 t^{3} - 30) t

\frac{d t}{d t} = 1

\frac{d}{d t} (3 t^{3} - 30) = 9 t^{2}

= 1 \cdot (3 t^{3} - 30) + 9 t^{2} t

Simplify

1 \cdot (3 t^{3} - 30) + 9 t^{2} t : 12 t^{3} - 30

= 12 t^{3} - 30

7 (x - 1 = 3 x - 1)

\frac{3 ( 2 x - 1 )}{5}

m u lt i pl y (- 5 x) (7 x + 2)

- 2 (a + b e) + (a + b e)^{2} + e - 1

, - 25 (x - 2) + 50 (y + 3) + 25 (z - 8)

What is the d/(dt)((x)(3x^3-30)) ?
The d/(dt)((x)(3x^3-30)) is 12t^3-30
What is the first d/(dt)((x)(3x^3-30)) ?
The first d/(dt)((x)(3x^3-30)) is 12t^3-30