What is expand (3(3x+4))/((x-4)(x+4)) ?

The solution to expand (3(3x+4))/((x-4)(x+4)) is (9x+12)/(x^2-16)

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expand (3(3x+4))/((x-4)(x+4))

expand

\frac{3 ( 3 x + 4 )}{( x - 4 ) ( x + 4 )}

\frac{9 x + 12}{x ^{2} - 16}

Solution steps

\frac{3 ( 3 x + 4 )}{( x - 4 ) ( x + 4 )}

Expand

(x - 4) (x + 4) : x^{2} - 16

= \frac{3 ( 3 x + 4 )}{x ^{2} - 16}

Expand

3 (3 x + 4) : 9 x + 12

= \frac{9 x + 12}{x ^{2} - 16}

(\frac{- 36}{9} bi g)^{2} (9 - 36) 2

\frac{( x + y )}{( x - y ) ( x - 2 y )}

\frac{( 1 - 2 x )}{( 5 - x ) ( 3 - x )}

\frac{5 n - 12}{10}

\frac{( z + y ) ( z - y )}{2}

What is expand (3(3x+4))/((x-4)(x+4)) ?
The solution to expand (3(3x+4))/((x-4)(x+4)) is (9x+12)/(x^2-16)