What is expand 2(2/3 e^x+e^{-2x}) ?

The solution to expand 2(2/3 e^x+e^{-2x}) is 4/3 e^x+2e^{-2x}

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expand 2(2/3 e^x+e^{-2x})

expand

2 (\frac{2}{3} e^{x} + e^{- 2 x})

\frac{4}{3} e^{x} + 2 e^{- 2 x}

Solution steps

2 (\frac{2}{3} e^{x} + e^{- 2 x})

Apply the distributive law:

a (b + c) = ab + a c

a = 2, b = \frac{2}{3} e^{x}, c = e^{- 2 x}

= 2 \cdot \frac{2}{3} e^{x} + 2 e^{- 2 x}

2 \cdot \frac{2}{3} e^{x} = \frac{4}{3} e^{x}

= \frac{4}{3} e^{x} + 2 e^{- 2 x}

[(1 - x) (- e^{- x})] - 1

\frac{( 2 - x - y ) ^{3}}{3}

\frac{1}{( y - 1 ) ^{3}}

z (u, v, w (z, u, v)) (2 u + v - w (z, u, v) + 3 z (u, v, w (z, u, v)) = 0)

126 + 32

What is expand 2(2/3 e^x+e^{-2x}) ?
The solution to expand 2(2/3 e^x+e^{-2x}) is 4/3 e^x+2e^{-2x}