What is expand 4(2sin(x-2t)+2e^{x+2t}) ?

The solution to expand 4(2sin(x-2t)+2e^{x+2t}) is 8sin(x-2t)+8e^{x+2t}

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expand 4(2sin(x-2t)+2e^{x+2t})

expand

4 (2 sin (x - 2 t) + 2 e^{x + 2 t})

8 sin (x - 2 t) + 8 e^{x + 2 t}

Solution steps

4 (2 sin (x - 2 t) + 2 e^{x + 2 t})

Apply the distributive law:

a (b + c) = ab + a c

a = 4, b = 2 sin (x - 2 t), c = 2 e^{x + 2 t}

= 4 \cdot 2 sin (x - 2 t) + 4 \cdot 2 e^{x + 2 t}

Multiply the numbers:

4 \cdot 2 = 8

= 8 sin (x - 2 t) + 8 e^{x + 2 t}

\frac{( ( x + 1 ) ( x + 2 ) ( 2 x + 3 ) )}{6}

\frac{6 x - 42}{( x - 4 ) ( x - 6 )}

cos (π (0.5 + h))

- \frac{5}{( x + 2 ) ( x - 3 )}

(12 x + 4 y = 15, 2) (32 x + 12 y = 420)

What is expand 4(2sin(x-2t)+2e^{x+2t}) ?
The solution to expand 4(2sin(x-2t)+2e^{x+2t}) is 8sin(x-2t)+8e^{x+2t}