What is ((x^3)/(x^2))^{-1} ?

The solution to ((x^3)/(x^2))^{-1} is 1/x

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simplify ((x^3)/(x^2))^{-1}

simplify

(\frac{x ^{3}}{x ^{2}})^{- 1}

\frac{1}{x}

Solution steps

(\frac{x ^{3}}{x ^{2}})^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

(\frac{x ^{3}}{x ^{2}})^{- 1} = \frac{1}{\frac{x ^{3}}{x ^{2}}}

= \frac{1}{\frac{x ^{3}}{x ^{2}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{x ^{2}}{x ^{3}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{x ^{2}}{x ^{3}} = \frac{1}{x ^{3 - 2}}

= \frac{1}{x ^{3 - 2}}

Subtract the numbers:

3 - 2 = 1

= \frac{1}{x}

- 5 < 6 x + 1 < 25

n + 1 \leq - 3 or - 4 n < - 8

\frac{73}{100} \cdot (- \frac{2}{7})

3 \cdot 2

lo g_{16} (\frac{1}{2}) = x