What is expand 1/(s(s+3)(s-1)) ?

The solution to expand 1/(s(s+3)(s-1)) is 1/(s^3+2s^2-3s)

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expand 1/(s(s+3)(s-1))

expand

\frac{1}{s ( s + 3 ) ( s - 1 )}

\frac{1}{s ^{3} + 2 s ^{2} - 3 s}

Solution steps

\frac{1}{s ( s + 3 ) ( s - 1 )}

Expand

s (s + 3) (s - 1) : s^{3} + 2 s^{2} - 3 s

= \frac{1}{s ^{3} + 2 s ^{2} - 3 s}

x^{2} + 2 ((x - 2) (a + h))

e^{x} (- e^{- x} + e^{- x} x)

\frac{d}{d y} ((x) (x^{3} + x y^{2}))

\frac{t + 10}{( t + 1 ) ( t ^{2} - 1 )}

π (10 x + 9)^{2}

What is expand 1/(s(s+3)(s-1)) ?
The solution to expand 1/(s(s+3)(s-1)) is 1/(s^3+2s^2-3s)