What is expand 3(x+7=2(2x+5)) ?

The solution to expand 3(x+7=2(2x+5)) is 3x+21=4x+10

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expand 3(x+7=2(2x+5))

expand

3 (x + 7 = 2 (2 x + 5))

3 x + 21 = 4 x + 10

Solution steps

3 (x + 7 = 2 (2 x + 5))

= 3 (x + 7 \cdot 2 = (2 x + 5))

Apply the distributive law:

a (b + c) = ab + a c

a = 3, b = x, c = 7 = 2 (2 x + 5)

3 x + 3 \cdot 7 = 2 (2 x + 5)

Simplify

3 x + 3 \cdot 7 = 2 (2 x + 5) : 3 x + 21 = 4 x + 10

3 x + 21 = 4 x + 10

\frac{10 s + 1}{s ( s + 4 )}

\frac{x ( x ^{2} - 1 )}{x + 5}

\frac{1}{( x - y ) ^{2}}

(4 a b^{2} - 11 d^{2} e)^{2}

2 (\frac{1}{y} + 3 y = 5)

What is expand 3(x+7=2(2x+5)) ?
The solution to expand 3(x+7=2(2x+5)) is 3x+21=4x+10