What is the d/(dy)((x)(-8x-13y+39)) ?

The d/(dy)((x)(-8x-13y+39)) is -13x

What is the first d/(dy)((x)(-8x-13y+39)) ?

The first d/(dy)((x)(-8x-13y+39)) is -13x

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\frac{d}{d y} ((x) (- 8 x - 13 y + 39))

- 13 x

Solution steps

\frac{d}{d y} ((x) (- 8 x - 13 y + 39))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x \frac{d}{d y} (- 8 x - 13 y + 39)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= x (- \frac{d}{d y} (8 x) - \frac{d}{d y} (13 y) + \frac{d}{d y} (39))

\frac{d}{d y} (8 x) = 0

\frac{d}{d y} (13 y) = 13

\frac{d}{d y} (39) = 0

= x (- 0 - 13 + 0)

Simplify

= - 13 x

\frac{( y + 1 ) ( y - 1 )}{y ^{2} + 1}

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2 (t + t^{2} + 2 e^{2 t})

2 [(2 p - q) d]

What is the d/(dy)((x)(-8x-13y+39)) ?
The d/(dy)((x)(-8x-13y+39)) is -13x
What is the first d/(dy)((x)(-8x-13y+39)) ?
The first d/(dy)((x)(-8x-13y+39)) is -13x