What is expand (5x+y=8,)(2x-y=-1) ?

The solution to expand (5x+y=8,)(2x-y=-1) is 5*2xx-5xy=-5*1*x+y=8,2x-y=8,y=-y=8,1

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expand (5x+y=8,)(2x-y=-1)

expand

(5 x + y = 8,) (2 x - y = - 1)

5 \cdot 2 xx - 5 x y = - 5 \cdot 1 \cdot x + y = 8, 2 x - y = 8, y = - y = 8, 1

Solution steps

(5 x + y = 8,) (2 x - y = - 1)

= (5 x + 8 =, y) (2 x - = y - 1)

Distribute parentheses

5 x \cdot 2 x + 5 x (- y =) + 5 x (- 1) + y = 8, 2 x + y = 8, (- y =) + y = 8, (- 1)

Apply minus-plus rules

+ (- a) = - a

5 \cdot 2 xx - 5 x y = - 5 \cdot 1 \cdot x + y = 8, 2 x - y = 8, y = - y = 8, 1

(sin (2 t) + 1) \cdot x (t - π)

(- 2 = 3 x^{2}) (12 x^{2} - 10 x + 6)

\frac{1}{s ^{2} ( s ^{2} + s + 1 )}

(1 - x^{2}) e^{x^{2}}

4 a^{2} + a^{2}

What is expand (5x+y=8,)(2x-y=-1) ?
The solution to expand (5x+y=8,)(2x-y=-1) is 5*2xx-5xy=-5*1*x+y=8,2x-y=8,y=-y=8,1