What is the d/(dy)((x)(xy+e^{xy})) ?

The d/(dy)((x)(xy+e^{xy})) is x(x+e^{xy}x)

What is the first d/(dy)((x)(xy+e^{xy})) ?

The first d/(dy)((x)(xy+e^{xy})) is x(x+e^{xy}x)

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\frac{d}{d y} ((x) (x y + e^{x y}))

x (x + e^{x y} x)

Solution steps

\frac{d}{d y} ((x) (x y + e^{x y}))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x \frac{d}{d y} (x y + e^{x y})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= x (\frac{d}{d y} (x y) + \frac{d}{d y} (e^{x y}))

\frac{d}{d y} (x y) = x

\frac{d}{d y} (e^{x y}) = e^{x y} x

= x (x + e^{x y} x)

x + (1 - x) \cdot ln (1 - x)

\frac{( e ^{- 3 π s} )}{( s - 1 ) ( s + 3 )}

\frac{2 ( 608 2 + 4 )}{3}

\frac{3 ( x - 2 )}{2}

(1 + i 3)^{27}

What is the d/(dy)((x)(xy+e^{xy})) ?
The d/(dy)((x)(xy+e^{xy})) is x(x+e^{xy}x)
What is the first d/(dy)((x)(xy+e^{xy})) ?
The first d/(dy)((x)(xy+e^{xy})) is x(x+e^{xy}x)