What is expand-4/9 (2z-3=1) ?

The solution to expand-4/9 (2z-3=1) is -(8z)/9+4/3 =1

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expand-4/9 (2z-3=1)

expand

- \frac{4}{9} (2 z - 3 = 1)

- \frac{8 z}{9} + \frac{4}{3} = 1

Solution steps

- \frac{4}{9} (2 z - 3 = 1)

= - \frac{4}{9} (2 z - 3 \cdot 1 =)

Apply the distributive law:

a (b - c) = ab - a c

a = - \frac{4}{9}, b = 2 z, c = 3 = 1

- \frac{4}{9} \cdot 2 z - (- \frac{4}{9}) \cdot 3 = 1

Apply minus-plus rules

- (- a) = a

- 2 \cdot \frac{4}{9} z + 3 \cdot \frac{4}{9} = 1

Expand

- 2 \cdot \frac{4}{9} z + 3 \cdot \frac{4}{9} : - \frac{8 z}{9} + \frac{4}{3}

- \frac{8 z}{9} + \frac{4}{3} = 1

a (- 1, - 1) b (- 1, 2) c (3, - 1)

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(2 x^{3} + 2 y) d x + (2 x + 3 y^{2}) d y

What is expand-4/9 (2z-3=1) ?
The solution to expand-4/9 (2z-3=1) is -(8z)/9+4/3 =1