What is expand (1-cos(x))sin(x)[0,pi] ?

The solution to expand (1-cos(x))sin(x)[0,pi] is 1*[0pi,]sin(x)-[0pi,]sin(x)cos(x)

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expand (1-cos(x))sin(x)[0,pi]

expand

(1 - cos (x)) sin (x) [0, π]

1 \cdot [0 π,] sin (x) - [0 π,] sin (x) cos (x)

Solution steps

(1 - cos (x)) sin (x) [0, π]

= [0 π,] sin (x) (1 - cos (x))

Apply the distributive law:

a (b - c) = ab - a c

a = sin (x) [0, π], b = 1, c = cos (x)

= sin (x) [0, π] \cdot 1 - sin (x) [0, π] cos (x)

= 1 \cdot [0 π,] sin (x) - [0 π,] sin (x) cos (x)

e^{t} \cdot (6 e^{t} - 8 t e^{t})

\frac{8 ( 2 x + 1 ) ( x + 1 )}{3 x ^{2}}

(x - 2 y = 6, 3) (x - 6 y = 18)

\frac{5 ( 11257 - 75 )}{64}

2 \frac{1}{4} (- 15.2)

What is expand (1-cos(x))sin(x)[0,pi] ?
The solution to expand (1-cos(x))sin(x)[0,pi] is 1*[0pi,]sin(x)-[0pi,]sin(x)cos(x)