What are the solutions to the equation 3m^2-5m-28=0 ?

The solutions to the equation 3m^2-5m-28=0 are m=4,m=-7/3

Find the zeros of 3m^2-5m-28=0

The zeros of 3m^2-5m-28=0 are m=4,m=-7/3

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3 m^{2} - 5 m - 28 = 0

m = 4, m = - \frac{7}{3}

Decimal Notation

m = 4, m = - 2.33333 \dots

Solution steps

3 m^{2} - 5 m - 28 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 3 ( - 28 )}{2 \cdot 3}

(- 5)^{2} - 4 \cdot 3 (- 28) = 19

m_{1, 2} = \frac{- ( - 5 ) \pm 19}{2 \cdot 3}

Separate the solutions

m_{1} = \frac{- ( - 5 ) + 19}{2 \cdot 3}, m_{2} = \frac{- ( - 5 ) - 19}{2 \cdot 3}

m = \frac{- ( - 5 ) + 19}{2 \cdot 3} : 4

m = \frac{- ( - 5 ) - 19}{2 \cdot 3} : - \frac{7}{3}

The solutions to the quadratic equation are:

m = 4, m = - \frac{7}{3}

44 x^{5} - 40 x^{4} - 4 x^{3}

(5 - 3) (5 + 3)

5 t - 26 = 18 t

lo g_{5} (25) = 3

- d^{2} + 10 d + 5 = 0

What are the solutions to the equation 3m^2-5m-28=0 ?
The solutions to the equation 3m^2-5m-28=0 are m=4,m=-7/3
Find the zeros of 3m^2-5m-28=0
The zeros of 3m^2-5m-28=0 are m=4,m=-7/3