What is expand sec^2(x)(1-sin^2(x)=1) ?

The solution to expand sec^2(x)(1-sin^2(x)=1) is sec^2(x)-sec^2(x)sin^2(x)=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand sec^2(x)(1-sin^2(x)=1)

expand

sec^{2} (x) (1 - sin^{2} (x) = 1)

sec^{2} (x) - sec^{2} (x) sin^{2} (x) = 1

Solution steps

sec^{2} (x) (1 - sin^{2} (x) = 1)

= sec^{2} (x) (1 - 1 = sin^{2} (x))

Apply the distributive law:

a (b - c) = ab - a c

a = sec^{2} (x), b = 1, c = sin^{2} (x) = 1

sec^{2} (x) \cdot 1 - sec^{2} (x) sin^{2} (x) = 1

1 \cdot sec^{2} (x) - sec^{2} (x) sin^{2} (x) = 1

Expand

1 \cdot sec^{2} (x) - sec^{2} (x) sin^{2} (x) : sec^{2} (x) - sec^{2} (x) sin^{2} (x)

sec^{2} (x) - sec^{2} (x) sin^{2} (x) = 1

\frac{( u + 1 ) ( u + 4 )}{u - 5}

\frac{5 ( 20 + 890 )}{49}

\frac{6}{( s ^{2} ( 2 s + 5 ) )}

π (n^{2} - 6 n + 9)

6 \cdot 7^{(x + 3)^{2}}

What is expand sec^2(x)(1-sin^2(x)=1) ?
The solution to expand sec^2(x)(1-sin^2(x)=1) is sec^2(x)-sec^2(x)sin^2(x)=1