What is expand (1+e^{2x})(-e^{2x}) ?

The solution to expand (1+e^{2x})(-e^{2x}) is -e^{2x}-e^{4x}

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expand (1+e^{2x})(-e^{2x})

expand

(1 + e^{2 x}) (- e^{2 x})

- e^{2 x} - e^{4 x}

Solution steps

(1 + e^{2 x}) (- e^{2 x})

Apply the distributive law:

a (b + c) = ab + a c

a = (- e^{2 x}), b = 1, c = e^{2 x}

= (- e^{2 x}) \cdot 1 + (- e^{2 x}) e^{2 x}

= 1 \cdot (- e^{2 x}) + e^{2 x} (- e^{2 x})

Simplify

1 \cdot (- e^{2 x}) + e^{2 x} (- e^{2 x}) : - e^{2 x} - e^{4 x}

= - e^{2 x} - e^{4 x}

\frac{4 π}{3} (r + 4)^{3}

cos (2 (k + 1))

3 x^{2} + ln (x) \cdot (2 x + ln (x))

(x^{2} y + 4 y) \cdot e^{y^{2}}

a \cdot b - (c + d) \cdot e

What is expand (1+e^{2x})(-e^{2x}) ?
The solution to expand (1+e^{2x})(-e^{2x}) is -e^{2x}-e^{4x}