What is expand-(3(b^2+b+6))/2 ?

The solution to expand-(3(b^2+b+6))/2 is -(3b^2)/2-(3b)/2-9

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expand-(3(b^2+b+6))/2

expand

- \frac{3 ( b ^{2} + b + 6 )}{2}

- \frac{3 b ^{2}}{2} - \frac{3 b}{2} - 9

Solution steps

- \frac{3 ( b ^{2} + b + 6 )}{2}

Expand

3 (b^{2} + b + 6) : 3 b^{2} + 3 b + 18

= - \frac{3 b ^{2} + 3 b + 18}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{3 b ^{2} + 3 b + 18}{2} = - (\frac{3 b ^{2}}{2}) - (\frac{3 b}{2}) - (\frac{18}{2})

= - (\frac{3 b ^{2}}{2}) - (\frac{3 b}{2}) - (\frac{18}{2})

Remove parentheses:

(a) = a

= - \frac{3 b ^{2}}{2} - \frac{3 b}{2} - \frac{18}{2}

Divide the numbers:

\frac{18}{2} = 9

= - \frac{3 b ^{2}}{2} - \frac{3 b}{2} - 9

\frac{5 ( - x + 4 )}{x ^{3}}

(\frac{- 20 - 2 y}{7})^{2}

\frac{2 s ^{2} + 6 s + 5}{( s + 2 ) ( s + 1 )}

x (e^{2 x} + x^{4})

(19 x^{2} - 2)^{\circ} (13 x - 9) (3)

What is expand-(3(b^2+b+6))/2 ?
The solution to expand-(3(b^2+b+6))/2 is -(3b^2)/2-(3b)/2-9