What is expand (x^3+2)/((x-1)^2) ?

The solution to expand (x^3+2)/((x-1)^2) is (x^3+2)/(x^2-2x+1)

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expand (x^3+2)/((x-1)^2)

expand

\frac{x ^{3} + 2}{( x - 1 ) ^{2}}

\frac{x ^{3} + 2}{x ^{2} - 2 x + 1}

Solution steps

\frac{x ^{3} + 2}{( x - 1 ) ^{2}}

(x - 1)^{2} = x^{2} - 2 x + 1

= \frac{x ^{3} + 2}{x ^{2} - 2 x + 1}

- \frac{5 ( 813 - 15 )}{49}

\frac{c ( 3 x - 1 )}{( x - 2 )}

- \frac{28 ( 4 s - 6 )}{s - 1}

\frac{14 x ( 1 - 2 x )}{( 1 - x ) ^{3}}

(2 x^{2} - 3 x + 1)^{5}

What is expand (x^3+2)/((x-1)^2) ?
The solution to expand (x^3+2)/((x-1)^2) is (x^3+2)/(x^2-2x+1)