What is expand-(2u(10-3y^4))/(3y) ?

The solution to expand-(2u(10-3y^4))/(3y) is -(20u)/(3y)+2uy^3

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expand-(2u(10-3y^4))/(3y)

expand

- \frac{2 u ( 10 - 3 y ^{4} )}{3 y}

- \frac{20 u}{3 y} + 2 u y^{3}

Solution steps

- \frac{2 u ( 10 - 3 y ^{4} )}{3 y}

Expand

2 u (10 - 3 y^{4}) : 20 u - 6 u y^{4}

= - \frac{20 u - 6 u y ^{4}}{3 y}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{20 u - 6 u y ^{4}}{3 y} = - (\frac{20 u}{3 y}) - (- \frac{6 u y ^{4}}{3 y})

= - (\frac{20 u}{3 y}) - (- \frac{6 u y ^{4}}{3 y})

Remove parentheses:

(a) = a, - (- a) = a

= - \frac{20 u}{3 y} + \frac{6 u y ^{4}}{3 y}

Cancel

\frac{6 u y ^{4}}{3 y} : 2 u y^{3}

= - \frac{20 u}{3 y} + 2 u y^{3}

x (1 + x^{3}) d x

(x - 2)^{2} + (y)^{2}

(3, 5, 9) \cdot (3 x, - 9 - 5 x, - 7 - 9 x)

(x + Δ x + 7) x + 7

\frac{3 ( 5 + 3 )}{8}

What is expand-(2u(10-3y^4))/(3y) ?
The solution to expand-(2u(10-3y^4))/(3y) is -(20u)/(3y)+2uy^3