What is expand ((9a+1)^3)/(27) ?

The solution to expand ((9a+1)^3)/(27) is 27a^3+9a^2+a+1/27

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expand ((9a+1)^3)/(27)

expand

\frac{( 9 a + 1 ) ^{3}}{27}

27 a^{3} + 9 a^{2} + a + \frac{1}{27}

Solution steps

\frac{( 9 a + 1 ) ^{3}}{27}

(9 a + 1)^{3} = 729 a^{3} + 243 a^{2} + 27 a + 1

= \frac{729 a ^{3} + 243 a ^{2} + 27 a + 1}{27}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{729 a ^{3} + 243 a ^{2} + 27 a + 1}{27} = \frac{729 a ^{3}}{27} + \frac{243 a ^{2}}{27} + \frac{27 a}{27} + \frac{1}{27}

= \frac{729 a ^{3}}{27} + \frac{243 a ^{2}}{27} + \frac{27 a}{27} + \frac{1}{27}

Divide the numbers:

\frac{729}{27} = 27

= 27 a^{3} + \frac{243 a ^{2}}{27} + \frac{27 a}{27} + \frac{1}{27}

Divide the numbers:

\frac{243}{27} = 9

= 27 a^{3} + 9 a^{2} + \frac{27 a}{27} + \frac{1}{27}

Divide the numbers:

\frac{27}{27} = 1

= 27 a^{3} + 9 a^{2} + a + \frac{1}{27}

\frac{9}{( x - 2 ) ^{2}}

(x + h) e

\frac{( 4 x ^{2} + y ) ^{2}}{x ^{2} + y}

\frac{3 x}{( x - 2 ) ( x + 4 )}

What is expand ((9a+1)^3)/(27) ?
The solution to expand ((9a+1)^3)/(27) is 27a^3+9a^2+a+1/27