What is expand 1/2 (e^x+3)e^{-2x}+C ?

The solution to expand 1/2 (e^x+3)e^{-2x}+C is 1/2 e^{-x}+3/2 e^{-2x}+C

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expand 1/2 (e^x+3)e^{-2x}+C

expand

\frac{1}{2} (e^{x} + 3) e^{- 2 x} + C

\frac{1}{2} e^{- x} + \frac{3}{2} e^{- 2 x} + C

Solution steps

\frac{1}{2} (e^{x} + 3) e^{- 2 x} + C

= \frac{1}{2} e^{- 2 x} (e^{x} + 3) + C

Expand

\frac{1}{2} e^{- 2 x} (e^{x} + 3) : \frac{1}{2} e^{- x} + \frac{3}{2} e^{- 2 x}

= \frac{1}{2} e^{- x} + \frac{3}{2} e^{- 2 x} + C

- ((- 10, - 4, - 2) + (4, 3, 5))

f (t - 2) H (t - 2)

(y + 3 x) d x

2 (x + 3 = 9)

(y^{2} - 1) \cdot \frac{d y}{d x}

What is expand 1/2 (e^x+3)e^{-2x}+C ?
The solution to expand 1/2 (e^x+3)e^{-2x}+C is 1/2 e^{-x}+3/2 e^{-2x}+C