What is expand ((2-x)^3)/(x^2) ?

The solution to expand ((2-x)^3)/(x^2) is 8/(x^2)-(12)/x+6-x

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expand ((2-x)^3)/(x^2)

expand

\frac{( 2 - x ) ^{3}}{x ^{2}}

\frac{8}{x ^{2}} - \frac{12}{x} + 6 - x

Solution steps

\frac{( 2 - x ) ^{3}}{x ^{2}}

(2 - x)^{3} = 8 - 12 x + 6 x^{2} - x^{3}

= \frac{8 - 12 x + 6 x ^{2} - x ^{3}}{x ^{2}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{8 - 12 x + 6 x ^{2} - x ^{3}}{x ^{2}} = \frac{8}{x ^{2}} - \frac{12 x}{x ^{2}} + \frac{6 x ^{2}}{x ^{2}} - \frac{x ^{3}}{x ^{2}}

= \frac{8}{x ^{2}} - \frac{12 x}{x ^{2}} + \frac{6 x ^{2}}{x ^{2}} - \frac{x ^{3}}{x ^{2}}

Cancel

\frac{12 x}{x ^{2}} : \frac{12}{x}

= \frac{8}{x ^{2}} - \frac{12}{x} + \frac{6 x ^{2}}{x ^{2}} - \frac{x ^{3}}{x ^{2}}

Cancel

\frac{6 x ^{2}}{x ^{2}} : 6

= \frac{8}{x ^{2}} - \frac{12}{x} + 6 - \frac{x ^{3}}{x ^{2}}

Cancel

\frac{x ^{3}}{x ^{2}} : x

= \frac{8}{x ^{2}} - \frac{12}{x} + 6 - x

2 x y d x + (y^{2} + x^{2}) d y

\frac{4}{( x ^{3} + 9 ) ^{5}}

\frac{3 ( 11 - 57 )}{4000}

2 (x + 3 = 0)

(x - 3)^{(x - 3) 2}

What is expand ((2-x)^3)/(x^2) ?
The solution to expand ((2-x)^3)/(x^2) is 8/(x^2)-(12)/x+6-x