What is expand ((-2x-1)(x+3))/(x(2x-1)) ?

The solution to expand ((-2x-1)(x+3))/(x(2x-1)) is (-2x^2-7x-3)/(2x^2-x)

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expand ((-2x-1)(x+3))/(x(2x-1))

expand

\frac{( - 2 x - 1 ) ( x + 3 )}{x ( 2 x - 1 )}

\frac{- 2 x ^{2} - 7 x - 3}{2 x ^{2} - x}

Solution steps

\frac{( - 2 x - 1 ) ( x + 3 )}{x ( 2 x - 1 )}

Expand

x (2 x - 1) : 2 x^{2} - x

= \frac{( - 2 x - 1 ) ( x + 3 )}{2 x ^{2} - x}

Expand

(- 2 x - 1) (x + 3) : - 2 x^{2} - 7 x - 3

= \frac{- 2 x ^{2} - 7 x - 3}{2 x ^{2} - x}

u (- 3, 1, - 1) + v (- 4, 5, 0)

\frac{( 5 + x ) \cdot x ^{14}}{4}

\frac{1}{4 ( s + 4 ) ^{2}}

(2 x e^{5} - 3) e^{3}

What is expand ((-2x-1)(x+3))/(x(2x-1)) ?
The solution to expand ((-2x-1)(x+3))/(x(2x-1)) is (-2x^2-7x-3)/(2x^2-x)