What is expand ((x+2)(x-3))/(3(x+3)) ?

The solution to expand ((x+2)(x-3))/(3(x+3)) is (x^2-x-6)/(3x+9)

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expand ((x+2)(x-3))/(3(x+3))

expand

\frac{( x + 2 ) ( x - 3 )}{3 ( x + 3 )}

\frac{x ^{2} - x - 6}{3 x + 9}

Solution steps

\frac{( x + 2 ) ( x - 3 )}{3 ( x + 3 )}

Expand

3 (x + 3) : 3 x + 9

= \frac{( x + 2 ) ( x - 3 )}{3 x + 9}

Expand

(x + 2) (x - 3) : x^{2} - x - 6

= \frac{x ^{2} - x - 6}{3 x + 9}

5 - 42 - 2

\frac{1}{x ^{2 (3 + 2 a)}}

\frac{2 ( x - y )}{- 4 - y}

(3 x - y + 2 z = 4) \cdot (- 2)

(4 e^{- 2 x} - e^{- 4 x})^{2}

What is expand ((x+2)(x-3))/(3(x+3)) ?
The solution to expand ((x+2)(x-3))/(3(x+3)) is (x^2-x-6)/(3x+9)