What is expand 1/((x^2-1)(x+2)(2x+1)) ?

The solution to expand 1/((x^2-1)(x+2)(2x+1)) is 1/(2x^4+5x^3-5x-2)

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expand 1/((x^2-1)(x+2)(2x+1))

expand

\frac{1}{( x ^{2} - 1 ) ( x + 2 ) ( 2 x + 1 )}

\frac{1}{2 x ^{4} + 5 x ^{3} - 5 x - 2}

Solution steps

\frac{1}{( x ^{2} - 1 ) ( x + 2 ) ( 2 x + 1 )}

Expand

(x^{2} - 1) (x + 2) (2 x + 1) : 2 x^{4} + 5 x^{3} - 5 x - 2

= \frac{1}{2 x ^{4} + 5 x ^{3} - 5 x - 2}

\frac{( x + 3 ) ( x + 1 )}{x ^{2} + 2 x + 3}

\frac{( 3 x + 1 ) ( x - 3 )}{( x + 4 )}

(1 - cos (x)) d x

Q (- 1, - 3)

(x^{3} + 8 x^{2} y + 12 y^{2}) d x

What is expand 1/((x^2-1)(x+2)(2x+1)) ?
The solution to expand 1/((x^2-1)(x+2)(2x+1)) is 1/(2x^4+5x^3-5x-2)