What is expand (2s+3)/((s+2)(s-3)(s+1)) ?

The solution to expand (2s+3)/((s+2)(s-3)(s+1)) is (2s+3)/(s^3-7s-6)

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expand (2s+3)/((s+2)(s-3)(s+1))

expand

\frac{2 s + 3}{( s + 2 ) ( s - 3 ) ( s + 1 )}

\frac{2 s + 3}{s ^{3} - 7 s - 6}

Solution steps

\frac{2 s + 3}{( s + 2 ) ( s - 3 ) ( s + 1 )}

Expand

(s + 2) (s - 3) (s + 1) : s^{3} - 7 s - 6

= \frac{2 s + 3}{s ^{3} - 7 s - 6}

\frac{5 ( 1097 - 5 )}{4}

\frac{4 + y}{( 2 x + y ) ^{2} + 12}

2 (7 x + 5 y = 21)

(1 + e^{- 2 x})^{2}

e^{i (x + y)}

What is expand (2s+3)/((s+2)(s-3)(s+1)) ?
The solution to expand (2s+3)/((s+2)(s-3)(s+1)) is (2s+3)/(s^3-7s-6)