What are the solutions to the equation 3x^2-6x-12=0 ?

The solutions to the equation 3x^2-6x-12=0 are x=1+sqrt(5),x=1-sqrt(5)

Find the zeros of 3x^2-6x-12=0

The zeros of 3x^2-6x-12=0 are x=1+sqrt(5),x=1-sqrt(5)

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3 x^{2} - 6 x - 12 = 0

x = 1 + 5, x = 1 - 5

Decimal Notation

x = 3.23606 \dots, x = - 1.23606 \dots

Solution steps

3 x^{2} - 6 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 3 ( - 12 )}{2 \cdot 3}

(- 6)^{2} - 4 \cdot 3 (- 12) = 65

x_{1, 2} = \frac{- ( - 6 ) \pm 6 5}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 6 5}{2 \cdot 3}, x_{2} = \frac{- ( - 6 ) - 6 5}{2 \cdot 3}

x = \frac{- ( - 6 ) + 6 5}{2 \cdot 3} : 1 + 5

x = \frac{- ( - 6 ) - 6 5}{2 \cdot 3} : 1 - 5

The solutions to the quadratic equation are:

x = 1 + 5, x = 1 - 5

n^{2} + 9 n - 400

8 k^{2} - 6 k - 9

k^{2} - 12 k + 23 = 0

- 8 x + 8 = - 3 x + 3

What are the solutions to the equation 3x^2-6x-12=0 ?
The solutions to the equation 3x^2-6x-12=0 are x=1+sqrt(5),x=1-sqrt(5)
Find the zeros of 3x^2-6x-12=0
The zeros of 3x^2-6x-12=0 are x=1+sqrt(5),x=1-sqrt(5)