What is expand (2-t)(\H(t-1)-\H(t-2)) ?

The solution to expand (2-t)(\H(t-1)-\H(t-2)) is 2\H(t-1)-2\H(t-2)-t\H(t-1)+t\H(t-2)

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expand (2-t)(\H(t-1)-\H(t-2))

expand

(2 - t) (H (t - 1) - H (t - 2))

2 H (t - 1) - 2 H (t - 2) - t H (t - 1) + t H (t - 2)

Solution steps

(2 - t) (H (t - 1) - H (t - 2))

Apply FOIL method:

(a + b) (c + d) = a c + a d + b c + b d

a = 2, b = - t, c = H (t - 1), d = - H (t - 2)

= 2 H (t - 1) + 2 (- H (t - 2)) + (- t) H (t - 1) + (- t) (- H (t - 2))

Apply minus-plus rules

+ (- a) = - a, (- a) (- b) = ab

= 2 H (t - 1) - 2 H (t - 2) - t H (t - 1) + t H (t - 2)

(a + b t)^{2} d t

\frac{x ^{2} ( x + 3 ) ^{2}}{x - 3}

(x e^{- x} + x) (x e^{- x} - x)

- e^{- r t} (x + u)^{0.5} + p (x - u)

\frac{2 ( 5 m + 1 )}{m - 6}

What is expand (2-t)(\H(t-1)-\H(t-2)) ?
The solution to expand (2-t)(\H(t-1)-\H(t-2)) is 2\H(t-1)-2\H(t-2)-t\H(t-1)+t\H(t-2)