What is expand (y-x)e^{y/x+1} ?

The solution to expand (y-x)e^{y/x+1} is e^{y/x+1}y-e^{y/x+1}x

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expand (y-x)e^{y/x+1}

expand

(y - x) e^{\frac{y}{x} + 1}

e^{\frac{y}{x} + 1} y - e^{\frac{y}{x} + 1} x

Solution steps

(y - x) e^{\frac{y}{x} + 1}

= e^{\frac{y}{x} + 1} (y - x)

Apply the distributive law:

a (b - c) = ab - a c

a = e^{\frac{y}{x} + 1}, b = y, c = x

= e^{\frac{y}{x} + 1} y - e^{\frac{y}{x} + 1} x

\frac{4}{( x + 8 ) ^{2}}

\frac{e ^{- 5 s}}{( - 4 + s ) s}

Lu (t - 1)

7 - (7 e^{2} - 7 e^{7}) e^{5 x}

(\frac{- 40}{8} bi g)^{2} (8 - 40) 2

What is expand (y-x)e^{y/x+1} ?
The solution to expand (y-x)e^{y/x+1} is e^{y/x+1}y-e^{y/x+1}x