What is expand c_{3}(ln(x)+1) ?

The solution to expand c_{3}(ln(x)+1) is c_{3}ln(x)+c_{3}

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expand c_{3}(ln(x)+1)

expand

c_{3} (ln (x) + 1)

c_{3} ln (x) + c_{3}

Solution steps

c_{3} (ln (x) + 1)

Apply the distributive law:

a (b + c) = ab + a c

a = c_{3}, b = ln (x), c = 1

= c_{3} ln (x) + c_{3} \cdot 1

= c_{3} ln (x) + 1 \cdot c_{3}

Multiply:

1 \cdot c_{3} = c_{3}

= c_{3} ln (x) + c_{3}

y - 3 (2 y - 7 = 76)

\frac{2 s - 1}{25 ( s ^{2} + 2 s + 5 )}

\frac{( x ^{2} ( x + h ) - ( x ^{2} ) )}{h}

\frac{a}{( a + b ) ^{2}}

\frac{6 x ^{3}}{( x - 7 ) ^{2}}

What is expand c_{3}(ln(x)+1) ?
The solution to expand c_{3}(ln(x)+1) is c_{3}ln(x)+c_{3}