What is expand (5x^2)/((x-4)(x^2-9)) ?

The solution to expand (5x^2)/((x-4)(x^2-9)) is (5x^2)/(x^3-9x-4x^2+36)

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expand (5x^2)/((x-4)(x^2-9))

expand

\frac{5 x ^{2}}{( x - 4 ) ( x ^{2} - 9 )}

\frac{5 x ^{2}}{x ^{3} - 9 x - 4 x ^{2} + 36}

Solution steps

\frac{5 x ^{2}}{( x - 4 ) ( x ^{2} - 9 )}

Expand

(x - 4) (x^{2} - 9) : x^{3} - 9 x - 4 x^{2} + 36

= \frac{5 x ^{2}}{x ^{3} - 9 x - 4 x ^{2} + 36}

8 (e^{x} + 2)^{2}

π (5 - x^{2})^{2}

(x^{3} - 3 x^{2} + 4) d x

3 (3 x - 1 = 4)

\frac{6 - 11 x}{( 3 x - 1 ) ( x + 2 )}

What is expand (5x^2)/((x-4)(x^2-9)) ?
The solution to expand (5x^2)/((x-4)(x^2-9)) is (5x^2)/(x^3-9x-4x^2+36)