What is the d/(dk)((e)(e-mk^2)) ?

The d/(dk)((e)(e-mk^2)) is -2emk

What is the first d/(dk)((e)(e-mk^2)) ?

The first d/(dk)((e)(e-mk^2)) is -2emk

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\frac{d}{d k} ((e) (e - m k^{2}))

- 2 e mk

Solution steps

\frac{d}{d k} ((e) (e - m k^{2}))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= e \frac{d}{d k} (e - m k^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= e (\frac{d e}{d k} - \frac{d}{d k} (m k^{2}))

\frac{d e}{d k} = 0

\frac{d}{d k} (m k^{2}) = 2 mk

= e (0 - 2 mk)

Simplify

= - 2 e mk

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