What is expand 2[xy(3x+3y)]+x^3+y^3-3xy ?

The solution to expand 2[xy(3x+3y)]+x^3+y^3-3xy is 6x^2y+6xy^2+x^3+y^3-3xy

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expand 2[xy(3x+3y)]+x^3+y^3-3xy

expand

2 [x y (3 x + 3 y)] + x^{3} + y^{3} - 3 x y

6 x^{2} y + 6 x y^{2} + x^{3} + y^{3} - 3 x y

Solution steps

2 (x y (3 x + 3 y)) + x^{3} + y^{3} - 3 x y

Remove parentheses:

(a) = a

= 2 x y (3 x + 3 y) + x^{3} + y^{3} - 3 x y

Expand

2 x y (3 x + 3 y) : 6 x^{2} y + 6 x y^{2}

= 6 x^{2} y + 6 x y^{2} + x^{3} + y^{3} - 3 x y

- 5^{2}

- \frac{a ^{2} ( 5 ab + 6 a b ^{2} )}{30}

(1 - e^{- x t})^{2}

sin (t y (y - 2))

4 u + 3 (- 1, 2) 6 u - 5 (3, - 2)

What is expand 2[xy(3x+3y)]+x^3+y^3-3xy ?
The solution to expand 2[xy(3x+3y)]+x^3+y^3-3xy is 6x^2y+6xy^2+x^3+y^3-3xy