What are the solutions to the equation -x^2+3x+18=0 ?

The solutions to the equation -x^2+3x+18=0 are x=-3,x=6

Find the zeros of -x^2+3x+18=0

The zeros of -x^2+3x+18=0 are x=-3,x=6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- x^{2} + 3 x + 18 = 0

x = - 3, x = 6

Solution steps

- x^{2} + 3 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 1 ) \cdot 18}{2 ( - 1 )}

3^{2} - 4 (- 1) \cdot 18 = 9

x_{1, 2} = \frac{- 3 \pm 9}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 3 + 9}{2 ( - 1 )}, x_{2} = \frac{- 3 - 9}{2 ( - 1 )}

x = \frac{- 3 + 9}{2 ( - 1 )} : - 3

x = \frac{- 3 - 9}{2 ( - 1 )} : 6

The solutions to the quadratic equation are:

x = - 3, x = 6

(x^{- \frac{12}{5}} \cdot y^{- \frac{3}{16}} \cdot 2^{\frac{4}{3}})^{\frac{5}{6}}

7 = \frac{4}{3} (x + 6)

49 x^{2} - 70 x + 25 = 64

x^{3} - 7 x^{2} + 14 x - 8

What are the solutions to the equation -x^2+3x+18=0 ?
The solutions to the equation -x^2+3x+18=0 are x=-3,x=6
Find the zeros of -x^2+3x+18=0
The zeros of -x^2+3x+18=0 are x=-3,x=6