What is expand ((k-2)(k-1))/((k+2)(k+1)) ?

The solution to expand ((k-2)(k-1))/((k+2)(k+1)) is (k^2-3k+2)/(k^2+3k+2)

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expand ((k-2)(k-1))/((k+2)(k+1))

expand

\frac{( k - 2 ) ( k - 1 )}{( k + 2 ) ( k + 1 )}

\frac{k ^{2} - 3 k + 2}{k ^{2} + 3 k + 2}

Solution steps

\frac{( k - 2 ) ( k - 1 )}{( k + 2 ) ( k + 1 )}

Expand

(k + 2) (k + 1) : k^{2} + 3 k + 2

= \frac{( k - 2 ) ( k - 1 )}{k ^{2} + 3 k + 2}

Expand

(k - 2) (k - 1) : k^{2} - 3 k + 2

= \frac{k ^{2} - 3 k + 2}{k ^{2} + 3 k + 2}

- \frac{( x + 1 ) ( x - 2 ) ( x - 3 )}{5}

\frac{( a + b )}{( a - b ) ^{2}}

\frac{3 x - 4}{( 5 x + 2 ) ^{3}}

- 1 + 6 cos (\frac{2 π}{7} (x - 5))

(x - 1)^{2} + (y - 2)^{2} - 25 P (5, - 1)

What is expand ((k-2)(k-1))/((k+2)(k+1)) ?
The solution to expand ((k-2)(k-1))/((k+2)(k+1)) is (k^2-3k+2)/(k^2+3k+2)