What is expand-1/(2(e^y+1)^2) ?

The solution to expand-1/(2(e^y+1)^2) is -1/(2e^{2y)+4e^y+2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand-1/(2(e^y+1)^2)

expand

- \frac{1}{2 ( e ^{y} + 1 ) ^{2}}

- \frac{1}{2 e ^{2 y} + 4 e ^{y} + 2}

Solution steps

- \frac{1}{2 ( e ^{y} + 1 ) ^{2}}

(e^{y} + 1)^{2} = e^{2 y} + 2 e^{y} + 1

= - \frac{1}{2 ( 2 e ^{y} + e ^{2 y} + 1 )}

Expand

2 (e^{2 y} + 2 e^{y} + 1) : 2 e^{2 y} + 4 e^{y} + 2

= - \frac{1}{4 e ^{y} + 2 e ^{2 y} + 2}

\frac{( h + 1 ) ^{2} ( h + 2 ) ^{2}}{4}

\frac{3 ( x - 2 )}{x - 3}

\frac{35 ( n + 1 ) ^{2}}{27 n ( n + 1 ) + 6}

\frac{4 - x}{x ( x ^{2} + 2 ) ^{2}}

x d y - 6 (y + x^{8}) d x

What is expand-1/(2(e^y+1)^2) ?
The solution to expand-1/(2(e^y+1)^2) is -1/(2e^{2y)+4e^y+2}