What is expand (x+δx)^2-4(x+δx) ?

The solution to expand (x+δx)^2-4(x+δx) is x^2+2δx^2+δ^2x^2-4x-4δx

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expand (x+δx)^2-4(x+δx)

expand

(x + δ x)^{2} - 4 (x + δ x)

x^{2} + 2 δ x^{2} + δ^{2} x^{2} - 4 x - 4 δ x

Solution steps

(x + δ x)^{2} - 4 (x + δ x)

Expand

- 4 (x + δ x) : - 4 x - 4 δ x

= (x + δ x)^{2} - 4 x - 4 δ x

(x + δ x)^{2} : x^{2} + 2 δ x^{2} + δ^{2} x^{2}

= x^{2} + 2 δ x^{2} + δ^{2} x^{2} - 4 x - 4 δ x

x^{2} (4 (x - 2)^{3})

(x - π)^{7}

\frac{( z ^{2} + 1 ) ( z ^{2} + 4 )}{z - 1}

t er m s (4 + 7 a^{2}) 2

sin (2) (π + x) - cos (x)

What is expand (x+δx)^2-4(x+δx) ?
The solution to expand (x+δx)^2-4(x+δx) is x^2+2δx^2+δ^2x^2-4x-4δx