What is expand 3(log_{3}(x)+log_{x}(3)=10) ?

The solution to expand 3(log_{3}(x)+log_{x}(3)=10) is 3log_{3}(x)+3log_{x}(3)=10

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expand 3(log_{3}(x)+log_{x}(3)=10)

expand

3 (lo g_{3} (x) + lo g_{x} (3) = 10)

3 lo g_{3} (x) + 3 lo g_{x} (3) = 10

Solution steps

3 (lo g_{3} (x) + lo g_{x} (3) = 10)

= 3 (lo g_{3} (x) + 10 = lo g_{x} (3))

Apply the distributive law:

a (b + c) = ab + a c

a = 3, b = lo g_{3} (x), c = lo g_{x} (3) = 10

3 lo g_{3} (x) + 3 lo g_{x} (3) = 10

x os (t - π)

\frac{2}{( s + 1 ) \cdot ( s - 3 )}

3 0^{2} x^{0.5522}

\frac{( x ^{2} + 8 ( y + 5 ) ^{2} )}{20}

1 - (\frac{1}{( 1 + x ) ^{20}})

What is expand 3(log_{3}(x)+log_{x}(3)=10) ?
The solution to expand 3(log_{3}(x)+log_{x}(3)=10) is 3log_{3}(x)+3log_{x}(3)=10