What is expand-2[x(x+3)(x-1)(x-4)] ?

The solution to expand-2[x(x+3)(x-1)(x-4)] is -2x^4+4x^3+22x^2-24x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand-2[x(x+3)(x-1)(x-4)]

expand

- 2 [x (x + 3) (x - 1) (x - 4)]

- 2 x^{4} + 4 x^{3} + 22 x^{2} - 24 x

Solution steps

- 2 (x (x + 3) (x - 1) (x - 4))

Remove parentheses:

(a) = a

= - 2 x (x + 3) (x - 1) (x - 4)

Expand

(x + 3) (x - 1) : x^{2} + 2 x - 3

= - 2 x (x^{2} + 2 x - 3) (x - 4)

Expand

(x^{2} + 2 x - 3) (x - 4) : x^{3} - 2 x^{2} - 11 x + 12

= - 2 x (x^{3} - 2 x^{2} - 11 x + 12)

Expand

- 2 x (x^{3} - 2 x^{2} - 11 x + 12) : - 2 x^{4} + 4 x^{3} + 22 x^{2} - 24 x

= - 2 x^{4} + 4 x^{3} + 22 x^{2} - 24 x

(e^{x} - 1) e^{x}

2^{x (1 - x)}

3 a - 4 b (a = 2, b = - 3)

x^{2} (x - 1) (x - 2) e^{x + s i n (x)}

\frac{( 3 w + 2 ) ( w + 2 )}{3 ( w ^{2} )}

What is expand-2[x(x+3)(x-1)(x-4)] ?
The solution to expand-2[x(x+3)(x-1)(x-4)] is -2x^4+4x^3+22x^2-24x