What is expand (((x^2)(25-x)))/((4pi)) ?

The solution to expand (((x^2)(25-x)))/((4pi)) is -(x^3)/(4pi)+(25x^2)/(4pi)

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expand (((x^2)(25-x)))/((4pi))

expand

\frac{( ( x ^{2} ) ( 25 - x ) )}{( 4 π )}

- \frac{x ^{3}}{4 π} + \frac{25 x ^{2}}{4 π}

Solution steps

\frac{( x ^{2} ) ( 25 - x )}{4 π}

Remove parentheses:

(a) = a

= \frac{x ^{2} ( 25 - x )}{4 π}

Expand

x^{2} (25 - x) : 25 x^{2} - x^{3}

= \frac{25 x ^{2} - x ^{3}}{4 π}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{25 x ^{2} - x ^{3}}{4 π} = \frac{25 x ^{2}}{4 π} - \frac{x ^{3}}{4 π}

= \frac{25 x ^{2}}{4 π} - \frac{x ^{3}}{4 π}

Rewrite in standard form

= - \frac{x ^{3}}{4 π} + \frac{25 x ^{2}}{4 π}

(2 x^{2} + 3 x + 1) (- 3 x^{4} + 2 x = 5)

(0, 2) y (- 3, - 2)

\frac{3 x - 1}{x ( x - 7 )}

\frac{- 1 - 2 x}{- b}

- 2 (x + ln (c))

What is expand (((x^2)(25-x)))/((4pi)) ?
The solution to expand (((x^2)(25-x)))/((4pi)) is -(x^3)/(4pi)+(25x^2)/(4pi)